What Does exp Mean in Mathematical Expressions?

  • #1
cryforhelp104
7
1
Homework Statement
What would "exp" in a question about approximating functions with Taylor Series mean?
Relevant Equations
exp(-ax^2) about the value x = 0 to second order in x
In my introductory modern physics class, I was asked to compute the Taylor Series for exp(-ax^2) about the value x = 0 to second order in x. I am unfamiliar with the what "exp" before the function means, despite having approximated functions with Taylor Series before. I think there was some gap in my previous math class. I'd appreciate a brief explanation (please don't work the problem, just explain the "exp" part)
 
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  • #2
It means ##e^{-ax^2}##, the exponential function. With this specific argument, it is also known as a Gaussian function (a very useful function).
 
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  • #3
cryforhelp104 said:
Homework Statement: What would "exp" in a question about approximating functions with Taylor Series mean?
Relevant Equations: exp(-ax^2) about the value x = 0 to second order in x

In my introductory modern physics class, I was asked to compute the Taylor Series for exp(-ax^2) about the value x = 0 to second order in x. I am unfamiliar with the what "exp" before the function means, despite having approximated functions with Taylor Series before. I think there was some gap in my previous math class. I'd appreciate a brief explanation (please don't work the problem, just explain the "exp" part)
Frabjous said:
It means ##e^{-ax^2}##, the exponential function. With this specific argument, it is also known as a gaussian function.
Welcome to PF, @cryforhelp104 -- Do you have what you need now to actually show some effort on this schoolwork problem of yours? :wink:
 
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  • #4
Thank you! So the question is to compute the Taylor Series for (e^(-ax^2)) about the value x = 0 to second order in x?
 
  • #5
cryforhelp104 said:
Thank you! So the question is to compute the Taylor Series for (e^(-ax^2)) about the value x = 0 to second order in x?
Yes.
 
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  • #6
A Taylor series in powers of x (expanded about x = 0) is a Maclaurin series. The Maclaurin series for ##e^x## is one of the simplest infinite series, where ##e^x = 1 + \frac x 1 + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots##.
Just do a substitution to get the Maclaurin series for ##e^{-ax^2}## for as many terms as are required and you're done.
 
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