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Loren Booda
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Consider a cone's surface with its vertex subtending a right angle and its base removed. If its interior were silvered, how would an observer on the axis of symmetry appear in its reflection?
Loren Booda said:Consider a cone's surface with its vertex subtending a right angle and its base removed. If its interior were silvered, how would an observer on the axis of symmetry appear in its reflection?
tiny-tim said:Hi Loren Booda!
Hint: try it for two planes at 90º first.
The image formed by light reflected from the interior of a cone with a height of r is a virtual image. This means that the light rays appear to come from a location behind the mirror, instead of in front of it.
The shape of the cone affects the image formed by light reflection because it determines the angle at which the light rays are reflected. A cone with a wider base will produce a larger and more distorted image, while a cone with a narrower base will produce a smaller and less distorted image.
The size and location of the image formed by light reflection from a cone are affected by the height and shape of the cone, as well as the angle at which the light rays strike the cone's interior. The distance between the object and the cone also plays a role in determining the size and location of the image.
No, the image formed by light reflected from a cone with r=h is not always upright. The orientation of the image depends on the position of the object relative to the cone and the angle at which the light rays are reflected. If the object is located above the cone's vertex, the image will be inverted.
The image formed by light reflection from a cone with r=h is different from that of a flat mirror because it is not a true image, but rather a virtual image. Additionally, the shape of the cone will cause the image to be distorted, whereas a flat mirror will produce a non-distorted image. The location and orientation of the image will also differ between a cone and a flat mirror.