- #1
laser
- 78
- 10
- Homework Statement
- See description
- Relevant Equations
- V=iR
I am uncertain if this represents situation (a) or situation (b).
i.e. is 2 = E-iR or is 2 = E? Or is the question ambiguous?
Thanks!
Is the r in your diagrams a representation of the internal resistance? If so, it is (b).laser said:Homework Statement: See description
Relevant Equations: V=iR
View attachment 344072
I am uncertain if this represents situation (a) or situation (b).
View attachment 344073
i.e. is 2 = E-iR or is 2 = E? Or is the question ambiguous?
Thanks!
Yesharuspex said:Is the r in your diagrams a representation of the internal resistance?
How would you envisage measuring the value ξ in diagram b? You'd have to put the probes 'somewhere' in amongst the electrolyte and electrodes. emf is a value of potential difference when no current.is being taken. Internal resistance is just a mental construct which gives a value to the amount of energy dissipated inside the battery for each unit of charge that passes through. We don't know where the loss occurs and nor do we find that the value of r is the same for all currents. r is a handy value to tell us things like how 'good' a battery is and what sort of load it will support.laser said:Homework Statement: See description
Relevant Equations: V=iR
is 2 = E-iR or is 2 = E? Or is the question ambiguous?
We measure current in series, voltage in parallel.Orodruin said:Amperemeters are the opposite, they are connected in parallel in the circuit
Yeah, I think that was just a typo in his reply, based on his "opposite" comment (which is correct). I've sent Oro a PM to clarify.DaveE said:We measure current in series, voltage in parallel.