Angle of incidence and reflection

In summary, the conversation discusses how to write a java code that calculates the angle at which a solid body bounces off a sphere of radius R, given the height at which the body approaches the sphere. The solution involves breaking down the velocity vector of the solid body into two components, one tangential to the sphere and one pointing towards the center. By reversing the direction of the central component and adding the two components together, the bounce off velocity vector can be obtained. The angle between the incident and reflected angle can then be divided by two to get the desired angle. Unfortunately, the code is not provided.
  • #1
Robben
166
2
I am trying to write a java code where the user inputs the height at which a solid body approaches a sphere of radius R and outputs the angle ##\theta## at which the body bounces off the sphere.

I have all my code written is just that I don't know how to derive the equation that calculates the angle ##\theta##.

https://col127.mail.live.com/att/GetAttachment.aspx?tnail=0&messageId=fbddf598-ac28-11e4-b241-00215ad73f00&Aux=114%7c0%7c8D20E4CE497FAD0%7c%7c0%7c0%7c0%7c0%7c%7c%7c10%7cmahjk17%40hotmail.com&cid=3d6363fe08a85f18&maxwidth=220&maxheight=160&size=Att&blob=MHxTY3JlZW4uanBnfGltYWdlL2pwZWc_3d
 

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  • #2
Break down the velocity vector of the solid body into two components: one is tangential to the sphere, another one points to the centre of the sphere. Reverse the direction of the central component and add the two component together and you will have the bounce off velocity vector. The angle between incident and reflected angle is what you need. Divide it by two and you will have the answer. Does it help?
 
  • #3
lowerlowerhk said:
Break down the velocity vector of the solid body into two components: one is tangential to the sphere, another one points to the centre of the sphere. Reverse the direction of the central component and add the two component together and you will have the bounce off velocity vector. The angle between incident and reflected angle is what you need. Divide it by two and you will have the answer. Does it help?

Hm, can you elaborate please?
 
  • #4
Robben said:
upload_2015-2-3_23-33-21-png.78612.png

Something wrong with your attachment.
 
  • #5
A.T. said:
Something wrong with your attachment.

I got it to work now.
 

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  • #6
can you post the code?
 

Related to Angle of incidence and reflection

1. What is the angle of incidence?

The angle of incidence is the angle formed between an incoming ray of light and the normal (perpendicular) line to the surface it is hitting.

2. How is the angle of incidence measured?

The angle of incidence is typically measured in degrees using a protractor or other angle-measuring tool. It is important to ensure that the normal line and the incoming ray are intersecting at the same point when measuring the angle.

3. What is the relationship between the angle of incidence and the angle of reflection?

According to the law of reflection, the angle of incidence is equal to the angle of reflection. This means that the incoming ray and the reflected ray will be at the same angle with respect to the normal line.

4. How does the angle of incidence affect the reflection of light?

The angle of incidence determines the direction and intensity of the reflected light. If the angle of incidence is small, the reflected ray will be closer to the normal line and the intensity of the reflection will be higher. If the angle of incidence is large, the reflected ray will be further from the normal line and the intensity of the reflection will be lower.

5. What are some practical applications of understanding the angle of incidence and reflection?

Understanding the angle of incidence and reflection is important in many fields, such as optics, photography, and architecture. It can also be used to create mirrors and other reflective surfaces, as well as to understand how light behaves when it hits different surfaces.

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