zeromodz said:D = VT
1 = (Vi+7)(T-0.2)
Vi = 1/(T-0.2) - 7
I have 2 unknowns and I don't know how to solve?
N-Gin said:You are almost done! You know the value of D, and by eliminating T from the first two equations you shold get the right answer.
Dickfore said:Hint: There's another relation between [itex]v_{i}[/itex] and [itex]t[/itex] that you have not taken into account.
zeromodz said:I have tried that, I just cannot find the answer.
zeromodz said:I have tried that, I just cannot find the answer.
zeromodz said:I can't solve it. I ended up with
V = 1/(1/V-0.2) - 7
Dickfore said:This is an equation with one unknown that can be further simplified. However, it is wrong because you had not converted 12 s into hours correctly.
Dickfore said:Get rid of the double fractions first and then multiply everything with the common denominator to get rid of fractions.
zeromodz said:V = 1/(1/V-0.00333) - 7
V = -V/0.003333 - 7
How is it incorrect? If you takeDickfore said:This is incorrect.
zeromodz said:How is it incorrect? If you take
1 / 2 / 3 = 3 / 2
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