What is the equation for calculating displacement based on acceleration?

In summary, an object initially at rest experiences a varying acceleration a, which is a function of its displacement d and can be represented by the equation a = cos(d/5 metre). To find the object's velocity after moving 3 metres, integration is required using the definition of acceleration. The given equation, d = 0.5*a^2, is not applicable in this scenario and may have been misquoted.
  • #1
24forChromium
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7

Homework Statement


An object is initially at rest, then, it receives a various acceleration a.
The acceleration is a function of its displacement d, given by the function a = cos (d/5 metre)
What is the object's velocity after moving 3 metres?

Homework Equations


d = 0.5*a^2
a = cos(d/5m) (question specific)

The Attempt at a Solution


This probably requires integration, of which I have basic understandings.

(Oh by the way, this is originally a problem dealing with a catapult, where the catapult's shaft is receiving a torque that varies with time (gravity's direction is unchanged but the tangent's direction does change) and I needed to calculate the final angular velocity after the shaft rotates a certain amount of angles. I thought the principle applies to linear motion too.)
 
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  • #2
Your relevant equation (single) is valid for constant acceleration, so it does not apply here. You will have to revert to the definition of acceleration and (as you already suspected) have to do an integration. Make a first step: what has to be integrated ?

[edit] Oops o:), as Andrew hints, your equation isn't even complete !
 
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  • #3
24forChromium said:

Homework Equations


d = 0.5*a^2
Where did you get that equation? Check the source.
 
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Related to What is the equation for calculating displacement based on acceleration?

What is the definition of integral for velocity?

The integral for velocity is the process of calculating the total displacement of an object over a given time period. It involves finding the area under the velocity-time graph, which represents the change in velocity over time.

Why is integral for velocity important?

Integral for velocity is important because it allows us to determine the total distance traveled by an object, even if the velocity is changing over time. It also helps us analyze the motion of an object and understand its acceleration and deceleration.

How is integral for velocity calculated?

The integral for velocity is calculated by taking the antiderivative of the velocity function and evaluating it at the given time interval. This can also be represented graphically by finding the area under the velocity-time graph.

What are the units of integral for velocity?

The units of integral for velocity depend on the units of velocity and time used in the calculation. Generally, it has units of distance, such as meters or kilometers.

Can integral for velocity be negative?

Yes, integral for velocity can be negative if the velocity is negative during certain time intervals. This indicates that the object is moving in the opposite direction of its initial motion. However, the overall displacement will still be positive or negative depending on the net distance traveled.

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