What is principal value integral?

[xylai]

In one paper (PRL 89, 144101 (2002)),
[tex]k=<Tr\sigma>_{p.v.}[/tex], (1)
where p.v. stipulates a principal-value evaluation and
[tex]<f>=^{def}lim_{t\rightarrow\infty}t^{-1}\int_{0}^{t}f(\bar{t})d\bar{t}[/tex].

[tex]\sigma_{n+1}=(\sigma_{n}^{-1}+T)^{-1}-\nabla\nabla f(q_{n+1})[/tex], (2)

then the author deduces the following equation:
[tex]k=lim_{N\rightarrow\infty}\sum_{n=0}^{N-1}ln|det(1+\sigma_{n}T)|[/tex] (3).
Can you show me how to deduce the equation (3)?
Thank you!

 

[xylai]

I have known how to deduce the equation (3)?
There is another equation:
[tex]\sigma (t)=(t+\sigma_{n}^{-1})^{-1}[/tex],
then
[tex]\int_{0}^{T}\sigma (t)=ln|det(1+\sigma_{n}T)|[/tex]

 

[lightarrow]

If [tex]x = x_0[/tex] is contained in the interval (a,b), then the Principal value of the Integral

[tex]
\int_{a}^{b}f(x)dx[/tex]

is:

[tex]P.V. \int_{a}^{b}f(x)dx\ =\ lim_{\epsilon\rightarrow 0^+} [\int_{a}^{x_0-\epsilon}f(x)dx\ +\ \int_{x_0+\epsilon}^{b}f(x)dx]
[/tex]

Note that the two separated limits or their sum can not exist, but the limit of their sum can, as in the case

[tex] f(x) = 1/x;\ x_0\ =\ 0[/tex]:

in this case, the two separated limits are infinite: one -oo and the other +oo, so their sum doesn't exist, but the limit of the sum (the principal value) is zero.

See also:
http://en.wikipedia.org/wiki/Cauchy_principal_value

 

[xylai]

If [tex]x = x_0[/tex] is contained in the interval (a,b), then the Principal value of the Integral

[tex]
\int_{a}^{b}f(x)dx[/tex]

is:

[tex]P.V. \int_{a}^{b}f(x)dx\ =\ lim_{\epsilon\rightarrow 0^+} [\int_{a}^{x_0-\epsilon}f(x)dx\ +\ \int_{x_0+\epsilon}^{b}f(x)dx]
[/tex]

Note that the two separated limits or their sum can not exist, but the limit of their sum can, as in the case

[tex] f(x) = 1/x;\ x_0\ =\ 0[/tex]:

in this case, the two separated limits are infinite: one -oo and the other +oo, so their sum doesn't exist, but the limit of the sum (the principal value) is zero.

See also:
http://en.wikipedia.org/wiki/Cauchy_principal_value

Thank you! you have talked about the principal value integral very clearly.