- #1
Jon.G
- 45
- 0
So I've got the equation for 'allowed angles of propagation':
SinΘp = pλ / 2πdnf
With p is the mode, λ the wavelength, d the width and n the refractive index.
I'm just not sure what to do with this equation, and my lecture notes don't go into any more detail.
For example, if I knew the the max number of modes (p) and I put this into the equation, would the value I get for the angle be the maximum value for propagation in this fibre?
I know this is probably something simple I should be able to figure out, but my mind is all over the place atm and I seem to be struggling to think things through and make simple connections :P
Thanks
SinΘp = pλ / 2πdnf
With p is the mode, λ the wavelength, d the width and n the refractive index.
I'm just not sure what to do with this equation, and my lecture notes don't go into any more detail.
For example, if I knew the the max number of modes (p) and I put this into the equation, would the value I get for the angle be the maximum value for propagation in this fibre?
I know this is probably something simple I should be able to figure out, but my mind is all over the place atm and I seem to be struggling to think things through and make simple connections :P
Thanks