- #1
Chrishtofu
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Homework Statement
The question is;
Two ropes hold a 200N weight as shown here; http://i.imgur.com/BgeoIVq.png
Find the tension in each rope using a vector diagram.
The forces are in equilibrium in the diagram btw.
Homework Equations
Well they gave us 200N so no need for F = MA
Rx = R * cos(theta)
Ry = R * sin(theta)
The above are resolution to component equations.
Other equations the teacher gave us were:
tan(theta) = Ry/Rx
R = SQRT[(Rx)^2 + (Ry)^2]
The above are component to resolution equations.
The Attempt at a Solution
So I fished around on this site and there were some solutions to this question, but I never quite got it, partially because (theta) for R2 is 90.
R1y = R1 * sin(53)
R2y = R2 * sin(90)
Downwards force = 200N
Therefore; because of equilibrium;
R1sin(53) + R2sin(90) = 200N [First Equation ( Y Axis )]
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R1x = R1 * cos(53)
R2x = R2 * cos(90)
Therefore; because of equilibrium;
R1cos(53) = R2(cos90) [Second Equation (X Axis)]
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Okay, the problem here is cos(90) = 0,
So does that mean that R1 = 0? because 0* R2 = 0...
So the answer I got is
R1 = 0
R2 = 200
Im pretty sure that I am wrong, but then again i only just started physics in year 11 (australia)