- #1
hivesaeed4
- 217
- 0
We're given x^2+2*y^2=1.
so x^2=1-2y^2
now using distance formula
d^2=x^2+y^2
since x^2=1-2y^2, substituting it in the distance formula we get:
d^2=1-2y^2+y^2=1-y^2;
differentiating and then setting the eq to 0 we get;
0=-4y
or y=0. now x^2=1-2y^2=1
so x=+-1
so point having min distance form origin is (+-1,0)
using the distance formula now
d^2=x^2+y^2
d=sqrt(1+0)=1
so x^2=1-2y^2
now using distance formula
d^2=x^2+y^2
since x^2=1-2y^2, substituting it in the distance formula we get:
d^2=1-2y^2+y^2=1-y^2;
differentiating and then setting the eq to 0 we get;
0=-4y
or y=0. now x^2=1-2y^2=1
so x=+-1
so point having min distance form origin is (+-1,0)
using the distance formula now
d^2=x^2+y^2
d=sqrt(1+0)=1