- #1
t.kirschner99
- 18
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1. Homework Statement
Three electrons form an equilateral triangle 1.00nm on each side. A proton is at the center of the triangle. What is the potential energy of this group of charges?
Known Variables:
s = 1.00 × 10-9m
p+ Charge = 1.60 × 10-19C
e- Charge = -1.60 × 10-19C
r = s/√(3) = 5.77 × 10-10m
ΔU = (kq1q2)/ r
[/B]
ΔU = k[(3(-1.60×10-19)2))/(1.00×10-9) - ((3(1.60×10-19)(-1.60×-19))/(5.77 × 10-10))]
For some reason I cannot get the answer, and I was wondering if anyone could spot my error. Thanks!
Three electrons form an equilateral triangle 1.00nm on each side. A proton is at the center of the triangle. What is the potential energy of this group of charges?
Known Variables:
s = 1.00 × 10-9m
p+ Charge = 1.60 × 10-19C
e- Charge = -1.60 × 10-19C
r = s/√(3) = 5.77 × 10-10m
Homework Equations
ΔU = (kq1q2)/ r
The Attempt at a Solution
[/B]
ΔU = k[(3(-1.60×10-19)2))/(1.00×10-9) - ((3(1.60×10-19)(-1.60×-19))/(5.77 × 10-10))]
For some reason I cannot get the answer, and I was wondering if anyone could spot my error. Thanks!