The effect of a field on a particle depends on the particle velocity?

In summary: Well, ##v=0## requires an exception :wink:Thank you...I know lorentz force...what I want from the question is to understand d'alembert's principle and what I meant by inertial force of the particle due to its kinetic energy is that when a force acts on a moving body it will follow some path I can have the same path if I assumed the particle is at rest and transformed the kinetic energy to force then apply the same force as the situation when it was movingI really still don't understand... Do you have a reference or an example?
  • #1
ahmadphy
3
0
Assume there is a force (vector field) on the space .....does the effect of this field on the particle(the change of momentum) at some position depend on the speed at that position? And is it related to the time interval dt the particle experiences this force ? Can i say dt=dx/v? And is that related to the inertial force of the particle due its kinetic energy?
 
Physics news on Phys.org
  • #2
Hello @ahmadphy ,
:welcome: ## \qquad## !​
ahmadphy said:
Assume there is a force (vector field) on the space .....does the effect of this field on the particle(the change of momentum) at some position depend on the speed at that position?
That is possible, yes. Example: charged particle in a magnetic field. Google Lorentz force.

ahmadphy said:
And is it related to the time interval dt the particle experiences this force ? Can i say dt=dx/v? And is that related to the inertial force of the particle due its kinetic energy?
The force itself does not depend on ##{\rm d} t##.
You can say ##{\rm d }t={\rm d} x/v## because that's the definition of ##v##.
[ edit ] mathematicians may frown on this...I don't know what 'the inertial force of the particle' means.

##\ ##
 
  • Like
Likes ahmadphy and vanhees71
  • #3
BvU said:
Hello @ahmadphy ,
:welcome: ## \qquad## !​

That is possible, yes. Example: charged particle in a magnetic field. Google Lorentz force.The force itself does not depend on ##{\rm d} t##.
You can say ##{\rm d }t={\rm d} x/v## because that's the definition of ##v##.
[ edit ] mathematicians may frown on this...I don't know what 'the inertial force of the particle' means.

##\ ##
Thank you...I know lorentz force...what I want from the question is to understand d'alembert's principle and what I meant by inertial force of the particle due to its kinetic energy is that when a force acts on a moving body it will follow some path I can have the same path if I assumed the particle is at rest and transformed the kinetic energy to force then apply the same force as the situation when it was moving
 
  • #4
ahmadphy said:
Thank you...I know lorentz force...what I want from the question is to understand d'alembert's principle and what I meant by inertial force of the particle due to its kinetic energy is that when a force acts on a moving body it will follow some path I can have the same path if I assumed the particle is at rest and transformed the kinetic energy to force then apply the same force as the situation when it was moving
Also when I asked if I can say that dt=dx/v is it always mathematically correct?
 
  • #5
ahmadphy said:
Also when I asked if I can say that dt=dx/v is it always mathematically correct?
Well, ##v=0## requires an exception :wink:
 
  • #6
ahmadphy said:
Thank you...I know lorentz force...what I want from the question is to understand d'alembert's principle and what I meant by inertial force of the particle due to its kinetic energy is that when a force acts on a moving body it will follow some path I can have the same path if I assumed the particle is at rest and transformed the kinetic energy to force then apply the same force as the situation when it was moving
I really still don't understand... Do you have a reference or an example?

##\ ##
 

Similar threads

  • Mechanics
Replies
7
Views
839
Replies
14
Views
1K
Replies
18
Views
1K
Replies
17
Views
2K
Replies
14
Views
1K
Replies
6
Views
1K
Replies
25
Views
1K
Replies
2
Views
1K
Back
Top