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krazykaci
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The initial speed of a body is 4.37 m/s. What is the speed after 2.06s if it accelerates uniformly at -3.93 m/s^2. Answer in units of m/s.
would I not use the kinamatic equ. v=v.+a(t) so v=4.37+-3.93(2.06)? cause when I do that I get the wrong solution?
would I not use the kinamatic equ. v=v.+a(t) so v=4.37+-3.93(2.06)? cause when I do that I get the wrong solution?