- #1
skrat
- 748
- 8
Homework Statement
Find Möbius transformation that maps:
a) circle ##|z+i|=1## into line ##Im(z)=2##
b) circle ##|z-i|=1## into line ##Im(z)=Re(z)##
c) line ##Re(z)=1## into circle ##|z|=2##
Homework Equations
##f(z)=\frac{az+b}{cz+d}##
The Attempt at a Solution
a) Firstly to move the circle into the origin ##f_1=z+i## than to map it into a line ##f_2=\frac{1-z}{z+1}## than rotate it for ##pi/2## with ##f_3=iz## and lastly move it upwards for ##2i## with ##f_4=z+2i##
So ##f=f_4\circ f_3\circ f_2\circ f_1=f_4(f_3(\frac{1-z-i}{z+1+i}))=\frac{1-z-i}{z+1+i}i+2i=\frac{3i+iz-1}{1+z+i}##
Is that ok?
b) To find a,b,c and d I determine that ##f(0)=0## and ##f(2i)=\infty ## and ##f(-1+i)=i## which gives me ##f_2=\frac{-z}{z-2i}##
Finally I have to rotate the line for ##pi/4## therefore the answer should be
##f(z)=\frac{-z}{z-2i}e^{-i\pi /4}##
c) Well, I know that ##\frac{1-z/2}{1+z/2}## maps circle (with radius 2) into right half-plane.
So I guess ##f(z)=\frac{2-z}{2+z}+1=\frac{4}{z+2}##
Now the inverse transformation is also the answer to part c): ##f(z)=\frac{4-2z}{z}##
What do you think?