Second order partial derivative

In summary: Try to be more explicit.In summary, the conversation is about finding the second order partial derivative operator on z, given that a and b are functions of z. The chain rule is used to calculate the derivatives, and the question of whether the given solution is correct is raised. Clarification is needed on what function is being differentiated.
  • #1
intervoxel
195
1

Homework Statement


a and b are functions of z:

a=a(z); b=b(z)

I want to calculate the second order partial derivative operator on z

Homework Equations


Using the chain rule:

[tex]
\frac{\partial}{\partial z}=\frac{\partial a}{\partial z}\frac{\partial}{\partial a}+\frac{\partial b}{\partial z}\frac{\partial}{\partial b}
[/tex]

The Attempt at a Solution


Is it correct?
[tex]
\frac{\partial^2}{\partial z^2}=\frac{\partial}{\partial a^2}+2\frac{\partial^2}{\partial a\partial b}+\frac{\partial^2}{\partial b^2}
[/tex]
 
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  • #2
Your problem is incompletely stated and uses poor notation and I think the answer is no anyway. It would be much clearer to use subscript notation for partial derivatives and ' for ordinary derivatives. Here is what I am guessing you are asking.

Let w = f(a,b) where a and b are functions of z. Differentiating with respect to z, the derivatives of a and b would be a' and b', not partial derivatives. The derivatives of w with respect to a and b would be partials: wa and wb. The derivative of w with respect to z would be w'. The chain rule gives:

w' = faa' + fbb'

This is your chain rule you have given in the relevant equations. Now you want to calculate w''.

w'' = (faa' + fbb')'

Can you take it from there?

= (fa)'a' + faa'' + (fb)'b' + fbb''
 
  • #3
intervoxel said:

Homework Statement


a and b are functions of z:

a=a(z); b=b(z)

I want to calculate the second order partial derivative operator on z
Do you mean that you want to think of z as a function of a and b and find
[tex]\frac{\partial^2 z}{\partial a^2}[/tex]
[tex]\frac{\partial^2 z}{\partial b^2}[/tex]
and
[tex]\frac{\partial^2 z}{\partial a\partial b}[/tex]?

Homework Equations


Using the chain rule:

[tex]
\frac{\partial}{\partial z}=\frac{\partial a}{\partial z}\frac{\partial}{\partial a}+\frac{\partial b}{\partial z}\frac{\partial}{\partial b}
[/tex]

The Attempt at a Solution


Is it correct?
[tex]
\frac{\partial^2}{\partial z^2}=\frac{\partial}{\partial a^2}+2\frac{\partial^2}{\partial a\partial b}+\frac{\partial^2}{\partial b^2}
[/tex]
This makes no sense at all. What function are you differentiating?

 

Related to Second order partial derivative

What is a second order partial derivative?

A second order partial derivative is a mathematical concept that represents the rate of change of a function with respect to two variables. It measures how much a function changes when both variables are changed simultaneously.

How is a second order partial derivative calculated?

A second order partial derivative is calculated by taking the partial derivative of the first derivative with respect to the same variable. This means taking the derivative of a derivative.

What is the significance of a second order partial derivative in science?

Second order partial derivatives are important in many scientific fields, especially in physics and engineering. They are used to model and understand complex systems and relationships between variables.

Can a second order partial derivative be negative?

Yes, a second order partial derivative can be negative. This indicates that the function is decreasing in one variable while increasing in the other, or vice versa.

How is a second order partial derivative represented mathematically?

A second order partial derivative is represented by a notation such as fxx, fxy, fyx, or fyy, where the first subscript indicates the variable that is being differentiated and the second subscript indicates the variable with respect to which the derivative is being taken.

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