- #1
godingly
- 13
- 0
Hey Dear forum,
I know I'm wrong, but I don't know why:
Since the Earth's descends 5 meters for every 8km, a horizontal speed of 8km/sec will put an object to rotate around the Earth (neglecting air resistance). I.e. in one second it will fall 5m below it's initial height, but so will the earth. But by the simple formula S = V[itex]_{o}[/itex]t + [itex]\frac{at^{2}}{2}[/itex] by the 2[itex]^{nd}[/itex] second it suppose to descend 20 meters from its original height - but the Earth would only curve by 10 (5*2)! Which means during the 1st and 2nd second it will crash into Earth!
What is my mistake?
I know I'm wrong, but I don't know why:
Since the Earth's descends 5 meters for every 8km, a horizontal speed of 8km/sec will put an object to rotate around the Earth (neglecting air resistance). I.e. in one second it will fall 5m below it's initial height, but so will the earth. But by the simple formula S = V[itex]_{o}[/itex]t + [itex]\frac{at^{2}}{2}[/itex] by the 2[itex]^{nd}[/itex] second it suppose to descend 20 meters from its original height - but the Earth would only curve by 10 (5*2)! Which means during the 1st and 2nd second it will crash into Earth!
What is my mistake?