Question about the 2nd law of thermodynamics (heat loss)

In summary, the conversation discusses the principles of the first and second laws of thermodynamics, specifically in relation to a closed system of a cylinder filled with ideal gas and a movable piston. The first law states that the change in heat energy (dQ) is equal to the change in internal energy (dU) plus the work done (dW). Meanwhile, the second law states that while mechanical energy can be fully converted into heat energy, the reverse is not possible. The question posed is how heat energy will be lost in a closed system with constant temperature, where dU is equal to 0 and dQ is equal to dU plus dW. It is mentioned that heat energy can be fully converted to work, but not through
  • #1
Shovon00000
3
0
Thread moved from the technical forums to the schoolwork forums
Assume that a closed system of cylindar filled with ideal gas consists of a movable piston.We know from the 1st law dQ=dU +dW.
According to the 2nd law mechanical energy can be totally converted into heat energy but heat energy cannot be converted completely into mechanical energy.The question is"If we give heat to the cylindar and keep the temperature constant how will some of the heat energy be lost ?(here dU=0,and we know dQ=dU+dW)
 
Physics news on Phys.org
  • #2
You can completely convert heat energy to work. You just can't do it by operating the system in a cycle.
 
  • Like
Likes TSny

Similar threads

  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
233
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
946
  • Introductory Physics Homework Help
Replies
1
Views
927
  • Introductory Physics Homework Help
Replies
3
Views
745
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
21
Views
1K
  • Introductory Physics Homework Help
Replies
33
Views
1K
Back
Top