- #1
mr_coffee
- 1,629
- 1
Hello everyone I'm having problems proving this:
note: A' will stand for complemented;
AB + BC'D' + A'BC + C'D = B + C'D
B(A+C'D')
B(A+C'+D')
BA + BC' + BD' + A'BC + C'D
BA + BD' + A'BC + C'(B+D)
B(A + D' + A'C) + C'(B+D)
now I'm stuck, i don't see how that is going to work out. Any help would be great.
note: A' will stand for complemented;
AB + BC'D' + A'BC + C'D = B + C'D
B(A+C'D')
B(A+C'+D')
BA + BC' + BD' + A'BC + C'D
BA + BD' + A'BC + C'(B+D)
B(A + D' + A'C) + C'(B+D)
now I'm stuck, i don't see how that is going to work out. Any help would be great.