- #1
kahless2005
- 46
- 0
A rubber block is subjected to an elongation of 0.03in along the x-axis, and its vertical faces are given a tilt so that theta=89.3deg. Find epsilonx, epsilony, and gammaxy. vr=0.5. The block is 4 in along the x-axis and 3 in along the y-axis.
My solution
epsilonx = 0.03/4 = .0075 in/in
gammaxy = pi/2 - theta = pi/2 - 89.3(pi/180) = .0122 rad
epsilony = - epsilonx/vr using Poisson's ratio = -.015 in/in
HOWEVER
The solutions states that
epsilony = - epsilonx*vr = -.00375 in/in
Why is this? This has been bugging me for three days
My solution
epsilonx = 0.03/4 = .0075 in/in
gammaxy = pi/2 - theta = pi/2 - 89.3(pi/180) = .0122 rad
epsilony = - epsilonx/vr using Poisson's ratio = -.015 in/in
HOWEVER
The solutions states that
epsilony = - epsilonx*vr = -.00375 in/in
Why is this? This has been bugging me for three days