I didn't understand what you mean here. Would you please clarify. Thanks a lotOrodruin said:the diagram with the exchange of one single photon, evaluates to zero.
Pi 0 Decay is a process in which a neutral pion (Pi 0) particle decays into either an electron-positron pair (e+ e-) and a photon (gamma) or only an electron-positron pair. This process is governed by the laws of quantum mechanics and is important in understanding the behavior of subatomic particles.
The chances of Pi 0 Decay resulting in e+ e- Gamma versus e+ e- only depend on the energy of the Pi 0 particle. At lower energies, the probability of e+ e- Gamma decay is higher, while at higher energies, the probability of e+ e- only decay is higher. This is because at higher energies, there is enough energy for the Pi 0 to decay into only an e+ e- pair, while at lower energies, it may not have enough energy to produce the additional photon.
The chances of e+ e- Gamma vs e+ e- only in Pi 0 Decay are affected by the energy of the Pi 0 particle, the conservation of energy and momentum, and the coupling constants of the particles involved. The spin and charge of the particles also play a role in determining the outcome of the decay.
Pi 0 Decay is studied and measured using particle accelerators, where high-energy collisions between particles can produce Pi 0 particles. These particles are then allowed to decay and the resulting particles are detected and measured. By studying the energy and momentum of the decay products, scientists can determine the probabilities of e+ e- Gamma vs e+ e- only decay.
Understanding Pi 0 Decay is important in understanding the behavior of subatomic particles and the fundamental laws of physics. It also has practical applications in fields such as particle physics, cosmology, and nuclear medicine. Additionally, studying Pi 0 Decay can provide insights into the early universe and the processes that govern the formation of matter.