Number of lines equidistant from four points on a plane

In summary, the conversation is about a mathematical problem with elementary solutions from a book. The solution is on page 41. The person trying to solve the problem is struggling with understanding how there can be 4 straight lines in one case. The other person clarifies that it is either four circles or three circles and a straight line, and explains how this can be possible.
  • #1
mahblah
21
2
Homework Statement
Four points in the plane are given, not all on the same straight line, and not all on a circle. How many straight lines and circles can be drawn which are equidistant from these points?
Relevant Equations
by distance from a point P to a circle c with center O we mean the lenght of the segment PQ, where Q is the point where the ray from O in the direction OP meets c
Hi, i'm trying to solve this problem.

It's exercise 3 on page 5 from this book:
Challenging mathematical problem with elementary solutions

The solution is on page 41:

1683625713913.png

1683626064255.png


I'm OK with the 4 circles in case 1: i can pick (inside/outside):
ABC + D,
ABD + C,
ADC + B,
BCD + A.
What i cannot understand is how there can be 4 straight lines in case 1:
if three points stand on one side of the equidistant line, these point must be collinear, and so there is only one possible straight line (i cannot re-arrange them!)

1683626234473.png


where am I wrong?

thanks
 
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  • #2
The phrasing of the answer lead to a misunderstanding. It is never four straight lines, it is either four circles or three circles and a straight line. If A, B, and C are collinear, then you can draw a straight line as you did, and three circles concentric with the circles passing through ABD, ACD, and BCD.
 
  • Like
Likes mahblah
  • #3
Oh that makes sense
Thanks!
 

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