- #1
Senjai
- 104
- 0
Homework Statement
This is not a homework question.
Understanding how [tex] log_{\frac{1}{2}}\frac{1}{9} = log_2x^2 [/tex]
The Attempt at a Solution
Somehow, the base of the first logarith was turned into 2^-1, no problem, but he was able to put the negative up in front of a log to equal:
[tex] -log_2\frac{1}{9} [/tex] How do you do that?