- #1
bosque
If $$\phi(t,x)$$ is a solution to the one dimensional wave equation and if the initial conditions $$\phi(0,x) , \phi_t(0,x)$$ are given, D'Alembert's Formula gives
$$\phi(t,x)= \frac 12[ \phi(0,x-ct)+ \phi(0,x+ct) ]+ \frac1{2c} \int_{x-ct}^{x+ct} \phi_t(0,y)dy . \tag{1}$$
which is commonly written (letting c = 1 and defining g and h)
$$\phi(t,x)= \frac 12[ g(x-t)+ g(x+t) ]+ \frac12 \int_{x-t}^{x+t} h(y)dy . \tag{2}$$
My question is:
What is the physically intuitive meaning of the integral term? I think I understand the displacement IC. It is the velocity IC that confuses me. I know h is the vertical displacement velocity (the time derivative of the vertical displacement) and the integral sums up the effects on the displacement of the velocity from each point on the x-axis between x-ct to x+ct. But, for just one example of my confusion, it doesn't seem that the points on the x-axis between x-ct and x+ct (excluding x-ct and x+ct) should contribute since they would reach the point (t,x) too early. For another example, velocity h is being integrated wrt distance not time so how does displacement result? I know the 1/c factor straightens out the dimensions but I am still confused. Does writing the differential as dy/c (in eq. 2) yield any insight? Maybe the x/t diagrams are confusing me. A diagram or drawing might help.
$$\phi(t,x)= \frac 12[ \phi(0,x-ct)+ \phi(0,x+ct) ]+ \frac1{2c} \int_{x-ct}^{x+ct} \phi_t(0,y)dy . \tag{1}$$
which is commonly written (letting c = 1 and defining g and h)
$$\phi(t,x)= \frac 12[ g(x-t)+ g(x+t) ]+ \frac12 \int_{x-t}^{x+t} h(y)dy . \tag{2}$$
My question is:
What is the physically intuitive meaning of the integral term? I think I understand the displacement IC. It is the velocity IC that confuses me. I know h is the vertical displacement velocity (the time derivative of the vertical displacement) and the integral sums up the effects on the displacement of the velocity from each point on the x-axis between x-ct to x+ct. But, for just one example of my confusion, it doesn't seem that the points on the x-axis between x-ct and x+ct (excluding x-ct and x+ct) should contribute since they would reach the point (t,x) too early. For another example, velocity h is being integrated wrt distance not time so how does displacement result? I know the 1/c factor straightens out the dimensions but I am still confused. Does writing the differential as dy/c (in eq. 2) yield any insight? Maybe the x/t diagrams are confusing me. A diagram or drawing might help.