- #1
mycotheology
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Heres the differential rate equation for a 0 order reaction in chemistry:
[itex]Rate = {{-d[A]} / {dt}} = k[/itex]
which can be rearranged to this:
[itex]-d[A] = dt k[/itex]
and when you integrate this you get the integrated rate equation but I don't understand how this works. The site I'm reading says you integrate both sides of the equation and get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord_z5.gif
is that supposed to be a definite integral or something? Anyhow, after integrating they get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord_z3.gif
I don't get it. Firstly [A] and t are variables so shouldn't they be raised a power and get divided by 2? In other words, shouldn't they become [itex][A]^{2} / 2[/itex] and [itex]t^{2} / 2[/itex]? Secondly, what's going on with the d. d means the change in something but I've never seen it been integrated before so I don't know what happens to it. Why did it disappear?
The 1st order equation has me equally confused:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord1_ip1.gif
integratin that, they get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord1-3.gif
has does d[A]/[A] become ln[A]?
[itex]Rate = {{-d[A]} / {dt}} = k[/itex]
which can be rearranged to this:
[itex]-d[A] = dt k[/itex]
and when you integrate this you get the integrated rate equation but I don't understand how this works. The site I'm reading says you integrate both sides of the equation and get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord_z5.gif
is that supposed to be a definite integral or something? Anyhow, after integrating they get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord_z3.gif
I don't get it. Firstly [A] and t are variables so shouldn't they be raised a power and get divided by 2? In other words, shouldn't they become [itex][A]^{2} / 2[/itex] and [itex]t^{2} / 2[/itex]? Secondly, what's going on with the d. d means the change in something but I've never seen it been integrated before so I don't know what happens to it. Why did it disappear?
The 1st order equation has me equally confused:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord1_ip1.gif
integratin that, they get this:
http://www.uni-regensburg.de/Fakultaeten/nat_Fak_IV/Organische_Chemie/Didaktik/Keusch/Grafik/ord1-3.gif
has does d[A]/[A] become ln[A]?
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