- #1
elessar_telkontar
- 16
- 0
I am gathering my mechanics notes and I put into it some examples. When I get the Hamilton principle I put a section for some basic variation calculus. There's the problem of brachistochrone, I try to solve it, but I get stuck with a integral:
the integral that I should make minimal is (I'm so sorry, but I don't know how to put it in LaTex):
t=int((sqrt(1+((dy/dx)^2))/sqrt(2gy))dx)
and from the variation calculus, the y must be the one that complies:
df/dy-(df/(dy/dx))/dx=0 where f=(sqrt(1+((dy/dx)^2))/sqrt(2gy)).
then calculating the partial derivatives of f and putting them into the eq:
m(1+((dy/dx)^2))+2y(dy/dx)(dm/dx)=0 or
m(1+(y'^2))+2yy'(dm/dx)
where y'=dy/dx and m=(1/f)(y'/(gy))
The question is how to integrate it? or which change of variable is good to integrate it in order to get the eq of the brachistochrone?
NOTE: I have tried to separate variables, but this is impossible.
the integral that I should make minimal is (I'm so sorry, but I don't know how to put it in LaTex):
t=int((sqrt(1+((dy/dx)^2))/sqrt(2gy))dx)
and from the variation calculus, the y must be the one that complies:
df/dy-(df/(dy/dx))/dx=0 where f=(sqrt(1+((dy/dx)^2))/sqrt(2gy)).
then calculating the partial derivatives of f and putting them into the eq:
m(1+((dy/dx)^2))+2y(dy/dx)(dm/dx)=0 or
m(1+(y'^2))+2yy'(dm/dx)
where y'=dy/dx and m=(1/f)(y'/(gy))
The question is how to integrate it? or which change of variable is good to integrate it in order to get the eq of the brachistochrone?
NOTE: I have tried to separate variables, but this is impossible.