- #1
Kawakaze
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- 0
Hi everyone, long time lurker, first time poster. Can someone please clear this up for me? Two wires running parallel to each other. I think its just an algebraic addition of the usual
B(r)=u_0i/2pir
but instead of r, we are using D and d
aslso i apologise for my formulae, if someone could point me to the tex thread ill redo them
By summing the magnetic field due to currents of magnitude i flowing in both the wires in the senses you found in part (c), show that, on the line joining the two wires, the magnetic field strength is given by =
`````````````````````````````````````````````````````
B(r)=u_0i/2pir
B=(u_0i/2piD)+(u_0i/2pid)
which i get to be
B=(u_0i)/pi(D^2-d^2)
the question says it should be
B=(u_0iD)/pi(D^2-d^2)
Where is that extra D on the numerator from?
Thanks
B(r)=u_0i/2pir
but instead of r, we are using D and d
aslso i apologise for my formulae, if someone could point me to the tex thread ill redo them
Homework Statement
By summing the magnetic field due to currents of magnitude i flowing in both the wires in the senses you found in part (c), show that, on the line joining the two wires, the magnetic field strength is given by =
`````````````````````````````````````````````````````
Homework Equations
B(r)=u_0i/2pir
The Attempt at a Solution
B=(u_0i/2piD)+(u_0i/2pid)
which i get to be
B=(u_0i)/pi(D^2-d^2)
the question says it should be
B=(u_0iD)/pi(D^2-d^2)
Where is that extra D on the numerator from?
Thanks