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Zoey Brown
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1. The
Lead is the final decay product of uranium-238 (half life = 4.7 billion years), so often the
uranium is embedded in lead. The decay of 1.00 g of uranium to thorium converts
6.83x10-8 kg of mass to energy. Assuming the uranium absorbs none of the heat, what
would be the temperature change of 120.0 kg of lead surrounding 1.00 g of uranium after
3.8 million years?
e=mc^2
mf=mi(0.5)^t/h
i got a really unreasonable answer; 394 035 degrees celcius
Lead is the final decay product of uranium-238 (half life = 4.7 billion years), so often the
uranium is embedded in lead. The decay of 1.00 g of uranium to thorium converts
6.83x10-8 kg of mass to energy. Assuming the uranium absorbs none of the heat, what
would be the temperature change of 120.0 kg of lead surrounding 1.00 g of uranium after
3.8 million years?
Homework Equations
e=mc^2
mf=mi(0.5)^t/h
The Attempt at a Solution
i got a really unreasonable answer; 394 035 degrees celcius