How Do You Solve These Blackbody Radiation Problems?

In summary, the two problems involve blackbody radiation and the maxima that occur at specific wavelengths. The first problem is that for a blackbody there is a frequency peak and a wavelennght peak. The second problem is that the maximum value Mw(max) at the wavelength w(max) in the distribution of blackbody radiation increases with T (temperature). To find the maximum you will need to differentiate with respect to the temperature and find the value of T that makes the derivative = 0. Right but what equations do I work with? The source of your question is not clear. I recommend the original poster refer to a textbook or course for the correct version of Plancks radiation law.
  • #1
Nebula
46
0
A couple Blackbody Problems?

I'm a little confused about these two problems involving blackbodies, hopefully someone could give me a bit of insight. Thanks in advance.

1. For a blackbody we there is a frequency peak and a wavelennght peak. Let's call em v and w respectively. Now consider the derivations of the maximums dependant on temperature to prove v*w not equal to the speed of light.

Im not sure what to do here. No were in my text do they talk about the derivations for the maximums. So I am not really sure in what direction to head.



next question.

2. The peak value Mw(max) at the wavelength w(max) in the distribution of blackbody radiation increases with T (temperature). Show Mw(max) depends on T as:
Mw(max)=CT^p
where C is some constant and power p
so we have to find the constant and the power.
 
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  • #2
The Planck distribution depends on the temperature. To find the maximum you will need to differentiate with respect to the temperature and find the value of T that makes the derivative = 0.
 
  • #3
Right but what equations do I work with?

Any ideas about 2?
 
  • #5
Hey Tide
In that page they give placnk's law as

((8*pi*v^2)/c^3)*...

But look at the following page why do they give Planck's law with the term
http://scienceworld.wolfram.com/physics/PlanckLaw.html

(2v^2)/c^2

Why is the term ((8*pi*v^2)/c^3) different than the one giving in scienceworld??
 
  • #6
P3X-018 said:
Hey Tide
In that page they give placnk's law as

((8*pi*v^2)/c^3)*...

But look at the following page why do they give Planck's law with the term
http://scienceworld.wolfram.com/physics/PlanckLaw.html

(2v^2)/c^2

Why is the term ((8*pi*v^2)/c^3) different than the one giving in scienceworld??

One might be a flux and the other an intensity - I didn't have time to study them carefully. I recommend the orginal poster refer to his textbook for the correct version!
 
  • #7
P3x,

I think for the problem at hand you should be focusing on the functional dependence which is
[tex]\frac {\nu ^3}{e^{\frac {h \nu}{kT}}-1}[/tex]
to find the peak.
 
  • #8
In the Physics Formulary, it says:
Planck's law for the energy distribution for the radiation of af black body is:

omega(v,T) = ((8pi*h*v^3)/c^3)*(exp(hv/kT)-1)^-1

"Energy distribution" is that the intensity or flux?
They define the flux as P/A
http://scienceworld.wolfram.com/physics/EnergyFlux.html

:S
 
  • #9
Edited:

Yes, I agree with that. It's the same as what I wrote - I just left off the normalization!
 
Last edited:
  • #10
So is this the flux:

omega(v,T) = ((8pi*h*v^3)/c^3)*(exp(hv/kT)-1)^-1 ?
 
  • #11
That looks good!
 

Related to How Do You Solve These Blackbody Radiation Problems?

1. What is a blackbody?

A blackbody is an idealized object that absorbs all incoming electromagnetic radiation (light) and emits it at all wavelengths. It is a theoretical concept used in physics and astronomy to study the behavior of light and heat.

2. What is the blackbody radiation curve?

The blackbody radiation curve is a graph that shows the amount of light emitted by a blackbody at different wavelengths. It follows a specific shape called the Planck curve, which depends on the temperature of the object.

3. What is the Stefan-Boltzmann law?

The Stefan-Boltzmann law is a fundamental law of physics that states the total energy emitted by a blackbody is directly proportional to the fourth power of its temperature. It is expressed as E=σT^4, where E is the energy, T is the temperature, and σ is the Stefan-Boltzmann constant.

4. What is Wien's displacement law?

Wien's displacement law states that the peak wavelength of radiation emitted by a blackbody is inversely proportional to its temperature. This means that as the temperature increases, the peak wavelength shifts to shorter (higher energy) wavelengths.

5. How do blackbodies relate to real-world objects?

Although blackbodies are theoretical concepts, they can be used to approximate the behavior of real-world objects. For example, the sun is often approximated as a blackbody to study its radiation and temperature. Additionally, many materials, such as metals, can behave like blackbodies under certain conditions.

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