- #1
ChiralSuperfields
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ChiralSuperfields said:Dose
I don't think you are correct. Why did you change the graph of f with the red dotted lines that are close to vertical?ChiralSuperfields said:Does someone please know whether I am correct?
Thank you for your reply @Mark44!Mark44 said:I don't think you are correct. Why did you change the graph of f with the red dotted lines that are close to vertical?
In your altered graph of f', the parts you added look way too steep to me.
Yes, pretty much. You could confirm that their graph of f' looks reasonable by tracing the graph of f on some graph paper, and then using a straight-edge at a number of points on the graph to estimate the derivative, and then plotting each of these estimates.ChiralSuperfields said:Do you please agree with the solutions then?
ChiralSuperfields said:Homework Statement: Please see below
Relevant Equations: Please see below
For this Problem 5,
View attachment 325718
The solution is,
View attachment 325719
However, I though the graph of f' would have end behavior more like,
View attachment 325720
Does someone please know whether I am correct?
Many thanks!
Furthermore in 5. (to explain why you are incorrect)TonyStewart said:f looks more like 4th order equation and f' looks like a 3rd order equation by counting the inflection points.
Your dotted line adds to more orders to change the direction of the asymptote of the derivative.
4. is a negative cosine function so that f' is easy to find.