Finding the projection of a Vector

In summary, the conversation discusses a possible mistake in a highlighted formula and the confusion between a vector unit and imaginary unit. The person is seeking confirmation and mentions the need for a better resource if there is indeed a mistake.
  • #1
chwala
Gold Member
2,662
352
Homework Statement
Kindly see attached.
Relevant Equations
vector knowledge
I am looking at this now; pretty straightforward as long as you are conversant with the formula: anyway i think there is a mistake on highlighted i.e
1689563985799.png
1689564008049.png
Ought to be

##-\dfrac{15}{37}(i+6j)##

just need a confirmation as at times i may miss to see something. If indeed its a mistake then its time to look for a better resource.
 
Last edited:
Physics news on Phys.org
  • #2
##1(3) + 6(-2) = 3 - 12 = -9##

Note the negative sign out front of the fraction.

-Dan
 
  • Like
Likes chwala
  • #3
Maybe you are confusing a vector unit ##\mathbf{i}## with imaginary unit i.
 
  • Like
Likes chwala
  • #4
topsquark said:
##1(3) + 6(-2) = 3 - 12 = -9##

Note the negative sign out front of the fraction.

-Dan
but

##\vec u= -i+4j+3k##

aaaaaargh let me take a break...thanks man.
 
  • #5
anuttarasammyak said:
Maybe you are confusing a vector unit ##\mathbf{i}## with imaginary unit i.
Actually, i was looking at the wrong question...you realise that i have posted a: question which is referenced to a totally different solution i.e b: solution.
 

Similar threads

  • Mechanical Engineering
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
30
Views
562
  • Calculus and Beyond Homework Help
Replies
2
Views
1K
  • STEM Academic Advising
Replies
23
Views
973
Replies
24
Views
2K
Replies
14
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
8
Views
5K
  • STEM Academic Advising
Replies
3
Views
752
Replies
6
Views
2K
  • Other Physics Topics
Replies
3
Views
1K
Back
Top