- #1
snoggerT
- 186
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Find the MacLaurin polynomial of degree 4 for f(x)
f(x)= (integral from 0 to x) sin(3t^2)
[f^(n)(0)/n!]*x^n
- I took the 4th derivative of sin(3t^2) and got:
f''''(x)= -108sin(3t^2)-1296t^2cos(3t^2)+1296t^4sin(3t^2)
Not real sure what to do from there. I plugged 0 in for t to find my f^(n)(0) and got 0,1,1,-1,-1 ...but I'm not sure if that's right. Can somebody please check my derivative and point me in the right direction for finding the series?
f(x)= (integral from 0 to x) sin(3t^2)
[f^(n)(0)/n!]*x^n
The Attempt at a Solution
- I took the 4th derivative of sin(3t^2) and got:
f''''(x)= -108sin(3t^2)-1296t^2cos(3t^2)+1296t^4sin(3t^2)
Not real sure what to do from there. I plugged 0 in for t to find my f^(n)(0) and got 0,1,1,-1,-1 ...but I'm not sure if that's right. Can somebody please check my derivative and point me in the right direction for finding the series?