Finding Additional Solutions for x^2 = 2^x Using Lambert W

  • Thread starter p.olly
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In summary, the Lambert W function is a special function that is the inverse of f(x)=xe^x. It is commonly used to solve equations involving both a variable and an exponent, such as x^2=2^x. By rewriting the equation and applying the Lambert W function, the solution can be found. For the equation x^2=2^x, there are two possible solutions, but only one of them is valid.
  • #1
p.olly
1
0
the obvious solutions are

x=2
x=4

but the other solutions i need to find using lambertW i think

but how do i bring this to the form of lambert W
 
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  • #2
What other solutions (implying more than one other solution than the obvious 2 and 4)? Are you supposed to solve this for real or complex x?

What work have you done? We have a template; you discarded that.
 

Related to Finding Additional Solutions for x^2 = 2^x Using Lambert W

What is the Lambert W function?

The Lambert W function, also known as the omega function, is a special function that is defined as the inverse of f(x)=xe^x. In other words, for a given value of y, the Lambert W function returns the value of x that satisfies the equation y=xe^x.

How is the Lambert W function used to solve equations?

The Lambert W function is commonly used to solve equations that involve both a variable and an exponent. It allows for the variable to be isolated on one side of the equation, making it easier to solve.

What is the equation x^2=2^x?

This equation is a type of exponential equation, where both sides contain variables raised to an exponent. It involves finding the value of x that satisfies the equation when x is equal to a power of 2.

How is the equation x^2=2^x solved using the Lambert W function?

The equation can be rewritten as x^2=e^(xln2). By taking the natural logarithm of both sides, we can isolate the variable and apply the Lambert W function to solve for x. The solution is x=-2W(-ln2).

What are the possible solutions for the equation x^2=2^x?

There are two possible solutions for this equation, which are x=2 and x=-2W(-ln2). However, the solution x=2 does not satisfy the original equation, so the only valid solution is x=-2W(-ln2).

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