What does Carnot's Theorem say about this?kelvin56484984 said:Homework Statement
If an engine operates between 250°C and 25°C, what is its maximum thermodynamic efficiency?Homework Equations
Ec=1-Tc/Th
The Attempt at a Solution
1-25/250
=90%
or
1-(25+273)/(250+273)
=43%
In this question,which one should I use K or ºC ?
thank you
Thermodynamic efficiency is a measure of the ratio between the amount of work or energy output from a system and the amount of energy input into the system. It is a measure of how well a system converts input energy into useful work.
The maximum thermodynamic efficiency is determined by using the Carnot efficiency formula, which is based on the Carnot cycle. This formula takes into account the temperature of the system and the temperature of the surroundings.
The maximum thermodynamic efficiency can be affected by several factors, including the temperature difference between the system and the surroundings, the type of energy conversion process, and any losses or inefficiencies within the system.
Finding the maximum thermodynamic efficiency is important because it allows us to understand the theoretical limit of a system's performance. It helps us to identify any potential improvements or inefficiencies within a system and can guide the design of more efficient systems.
No, the maximum thermodynamic efficiency cannot be greater than 100%. This is because it is a theoretical limit based on the Carnot cycle, which assumes that all energy input into the system is converted into useful work. In reality, there are always losses and inefficiencies that prevent a system from achieving 100% efficiency.