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ally2106
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As shown in Figure Q1a, a frictionless, massless, piston, supported by two springs, A and B, is held by a pin in a vacuum inside a rigid-walled container. The properties of the springs are: spring constants kA = 3,859 and kB = 3,090 (in N/m), natural lengths LA0 = 0.03 and LB0 = 0.1 (in m). When the piston is pinned to the wall, the lengths of the springs are LA1 = 0.1 and LB1 = 0.1 (in m), respectively. Both springs possesses dissipative properties so that after the pin is pulled, the piston eventually comes to rest at an equilibrium position. Find the length of spring A in this equilibrium position (LA2) in units of m.
Equations so far:
Models:
Elastic Energy Constituitive Relation: (E2 - E1) = (k/2)(x22 - x12)
First Law of thermodynamics: (E2 - E1) = (Q1-2) - (W1-2)
Second Law of thermodynamics...
Don't really know where to start? Help appreciated