- #36
WWGD
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Myb bad, thanks for pointing it out , for links and followup. I am editing as we speak.Infrared said:The proof does not consider the degree of a map ##X\to X##, but of a map ##X^4\to X^4##. This makes sense because ##X^4\cong\mathbb{R}^6##. I think @WWGD had a typo of ##X^6## for ##\mathbb{R}^6## in his post.