- #1
Zero
- 17
- 4
- Homework Statement
- A man (mass is 90.0 kg, 7.00 m/s east) runs towards a sled (mass is 100.0 kg, initially stationary) and jumps on to it (assume momentum is conserved). The sled (with the Agent on top of it) slides a total distance of 4.00 meters. Assume the sled only moves horizontally. Calculate the force due to friction acting on the sled.
- Relevant Equations
- So I know the formula for friction is Ff= U (Fn) but I have the normal force but I don't have U. I know I can get U but for that I need acceleration. I know I can get acceleration but I need time. But without sounding redundant am I missing something???
p man= mv
p man = 90 (7)
p man= 630
p sled= mv
p sled= 100 (0)
p sled= 0
p man+sled= 630 + 0
p man+sled= 630
fg man= mg
fg man= 90 (9.8)
fg man= 882
fg sled= mg
fg sled= 100 (9.8)
fg sled= 980
fg sled+man= 980+882
fg sled+man= 1862
p man = 90 (7)
p man= 630
p sled= mv
p sled= 100 (0)
p sled= 0
p man+sled= 630 + 0
p man+sled= 630
fg man= mg
fg man= 90 (9.8)
fg man= 882
fg sled= mg
fg sled= 100 (9.8)
fg sled= 980
fg sled+man= 980+882
fg sled+man= 1862