- #1
mortymoose
Homework Statement
[/B]
A short current element dl⃗ = (0.500 mm)j^ carries a current of 5.20 A in the same direction as dl⃗ . Point P is located at r⃗ = ( -0.730 m)i^+ (0.390m)k^.
Find the magnetic field at P produced by this current.
So basically what they are asking me for is the x, y, and z components of dB.
Homework Equations
dB= mu0/4pi * (I*(dl x r^)/r^2)
B=Bxi^ +Byj^ +Bzk^
The Attempt at a Solution
dB= 10^-7 * 5.2A *(1.95*10^-4m i^ +3.65*10^-4m k^ )/r^2
So, I cross multiplied dl and r^, now I am completely lost. I don't understand how I am supposed to find the x,y, and z components.
The idea i have is:
use the r^ as r and square it and finish the above equation and solve for dB, and then whatever i^ and k^ component is in the answer is equivalent to my x and z?
So dB=(-2.67*10^-4)i^ +(4.86*10^-10)k^
i^= x k^=z and y=0=j^But i get this answer wrong. Can anyone direct me into the right direction or tell me what I did wrong?