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Homework Statement
Working on a lab report, where we are asked to calculate the density of air.
Ambient Temperature: 19°C
Barometer (mm Hg abs): 765
There were two correction factors: 2.35 and 2.41
How do I use the above information to find the Air Density (kg/m3) ?
What are the correction factors? And, why did we take two correction factors?
Homework Equations
I know that: 1mm Hg = 133 Pa; and μ=1.8*10^-5 Nsm^-2
σ=δ/θ where δ=p_ambient/p_sls and θ=T_ambient/T_sls
We know that:
ρ_sls=1.225 kgm^(-3)
p_sls=760 mm Hg abs
T_sls=288 K (15°C)
Hence:
δ=p_ambient/(1.225 kgm^(-3) )= and θ=T_ambient/(288 K) =
Thus:
σ=δ/θ= δ/θ=
The Attempt at a Solution
Using ρ=p/(RT)
where T=292.15 K, R=0.287, p=101,745 Pa
But I just don't know how to use the correction factors. Should I take an average of both of them? Should I have two air densities?
Any help you make have would be much appreciated.
Thanks
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