Calculate the frequency, in hertz (level n = 10 to level n = 5)

[pinklemon]

Calculate the frequency, in hertz, of the photon that is emitted when a electron falls from level n = 10 to level n = 5 in the H atom.

Enter a numeric answer only, no units.

I tried asking in other places but ppl are so ambiguous about it.
:( please help me.

I used rydberg formula:
1/λ = RH ∙ (1/n₁² - 1/n₂²)
(RH rydberg constant for hydrogen, n₁ lower level, n₂ higher level)

Hence:
λ = 1/ [ 1.09678×10⁷m⁻¹ ∙ (1/5² - 1/10²) ] = 3.0392×10⁻⁶m

and then I converted to Hz = 9.89e14 but i still GOT IT wrong :( Please help me someone!

 

[Borek]

Check your math, 10^-6m doesn't look correct.

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methods

 

[Blueshift5]

The frequency, in hertz, of the photon emitted when an electron falls from level n = 10 to level n = 5 in the hydrogen atom can be calculated using the formula: f = E/h, where f is frequency, E is the energy difference between the two levels, and h is Planck's constant.

First, we can calculate the energy difference using the Rydberg formula: E = RH ∙ (1/n₁² - 1/n₂²) = 2.17987×10⁻¹⁸ J

Substituting this into the frequency formula, we get: f = (2.17987×10⁻¹⁸ J)/h = (2.17987×10⁻¹⁸ J)/(6.62607×10⁻³⁴ J∙s) = 3.2896×10¹⁴ Hz

Therefore, the frequency of the photon emitted when an electron falls from level n = 10 to level n = 5 in the hydrogen atom is 3.2896×10¹⁴ Hz.