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phospho
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Q. Show that the area between the positive x-axis, the y-axis and the curve [itex] y = ||e^x - 1| - 1| [/itex] is ln4 - 1
I've drawn the curve:
http://gyazo.com/cfd52af0f82e0e7d6b063681a73de45a
I notice for x < 0 (as I drew e^x to start out with, that's how I noticed it):
y = e^xfor x>ln(2) y = e^x - 2 (again, as I drew it before hand)
I can't seem to see what y will be for for 0≤x≤ln(2), as all my other notices are because I drew them beforehand.
Could anyone explain how I can split up y accordingly for x <0 for 0≤x≤ln(2) x > ln(2) ?
I've drawn the curve:
http://gyazo.com/cfd52af0f82e0e7d6b063681a73de45a
I notice for x < 0 (as I drew e^x to start out with, that's how I noticed it):
y = e^xfor x>ln(2) y = e^x - 2 (again, as I drew it before hand)
I can't seem to see what y will be for for 0≤x≤ln(2), as all my other notices are because I drew them beforehand.
Could anyone explain how I can split up y accordingly for x <0 for 0≤x≤ln(2) x > ln(2) ?