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a)
Our force can be represented as: $$\vec F= -k(r-H) \hat r$$ then the equations of motion are: $$\hat r: \ddot r -r {\dot{\theta}}^2=-\frac{k}{m_1}(r-H)$$ $$\hat{\theta}: r \ddot{\theta} + 2 \dot r \dot{\theta}=0$$
Plus we know that angular momentum is constant then $$|\vec L|=m r^2...
My solutions: When ball is launched horizontally, assuming its velocity is entirely in the horizontal dimension, there is no interaction of the ball with the gravitational field, thus no change in GPE, so all of the EPE (elastic potential energy ) of the spring is transferred to KE of the ball...
Hello All.
I am mentoring a high school student in my area with his class project for school. He has chosen he wants to launch an object (in our case, a softball) into a 5' diameter area. The idea is to build basically an oversized slingshot using an extension spring as the source of energy.
We...
Hello! I am stuck on part of a problem and was wondering what I am doing wrong. For part a of the problem, we were asked to find the impact speed. I did this in a photo below given the following values:
Θ = 30 degrees. The initial velocity = 10 m/s. The coefficient of kinetic friction = 0.4...
Hi everyone, just a quick question..
I tried this problem using Newtons laws, not conservation of energy, and I got an answer exactly half of what the correct answer is, and I'm not sure why. Here is what I did:
Net force = zero once the spring is compressed, therefore
mg - kx = 0
mg = kx...
Okay so, recently I got a job with my local newspaper delivering newspapers to make some money while deciding how I want to continue my educational career (I already have some college under my belt but I'm taking a semester off). All the newspapers have to be at the houses by 6 am so in order to...
Consider a spring with one end attached to a wall and the other to a free mass, which is then stretched so some potential energy U. After it has been released and has de-stretched, the change of elastic potential energy is -U which equates to the negative of the work done by the spring force on...
I wrote Newton's equations for the block seen from the non inertial frame. The axis are inclined.
##x) Fe+W_x-f*cos(\alpha)=0##
##y) N-f*sin(\alpha)-W_y=0##
Where ##f*## is the pseudo-force and ##Fe## is the elastic force. I set the acceleration as 0 because they are in equilibrium.
The thing...
I've solved all the cases in the non inertial system.
A) For ##m_1## we have
##x) P_{1x} -T=m.a_x##
##y) N_1 -P_{1y}=m.a_y##
For ##m_2## we have
##y) T+F_e -P_2=m.a_y##
As it moves with constant velocity I solve it setting ##a_x=0##. So for ##m_1## ##mgsin(\alpha)=T##, then I replace it in...
Do you have any information's about how to calculate the bias spring or the Force needed ? the current necessary to heat the SMA spring for a 4mm stroke ?
Thank you
This is a fun one, sort of!
I am working on a singing saw that can be amplified with a regular magnetic pick up, from an electric guitar.
I made a blade from laser cut1095 blue tempered spring steel (0.042" thick). It sounded great, but after a few months of service, the blade cracked.
What is a...
Homework Statement: A box of mass M=30 kg sits on a ramp which is tilted at angle 13 degrees. The coefficients of static and kinetic friction between the box and the ramp are both 0.12. The box is connected to a spring of spring constant k=9 Newtons per meter.
Initially, the box is held in...
I have a spring which I am using to cushion a simple device, but it has proven to be too stiff for the purpose. Is there a way to reduce the stiffness of a spring, without making it brittle or malleable?
I have access to ovens which can achieve 550°C, which can also quench in water or poly-oil...
I encountered a weird conflict between my thought process and that of author's solution in book:
The common viewpoint of both of us were invoking conservation of energy of this SHM system
But the author proceeds to solve it using conservation of momentum, taking the new mass added to system as...
Hola!
So my first approach to this is use both the conservation of energy and momentum equations since collision between the first two objects are elastic.
Let the 3 blocks be a,b and c (from left to right)
Does this means the following:
whereby
##v_{a} ##= speed of block a after collision...
Hi all. Multiple part problem that I'm really stuck on. I'll attach a file.
At first I had attempted the whole problem with the idea that fixed wall was a fixed point, and that the mass on a spring was a "free" point. But I learned later that the mass can't be treated like a "free" point since...
Classical problems for hookes law generally give either mass or spring constant.
What if I have a graph of a wavelike structure that is oscillating which I can use to measure for example: T (period), t (time), Δx (displacement), v (velocity), a (acceleration) and other variables is this...
I figured out that the spring constant is inversely proportional to the natural length, but there’s still an unknown change in a quantity( most likely extension).
How far will the spring extend, given that the block is not attached? Will it extend beyond its natural length? How to calculate at what point the box comes off the spring?
Dear all,
I am back with another Spring problem.
I have tried to use the insights I gained from your help last time:
https://www.physicsforums.com/threads/find-v-x-of-a-mass-suspended-from-a-spring.972942/page-3#post-6190934
I figured I start with calculating the new equilibrium by ## x...
if you drop a spring that is elongated via its only weight (slinky) vs another spring that is on its side... will both hit the ground at the same time?
I was looking at this spring to make a constant torque motor:
https://www.ondrives.com/sr119
They come in many sizes and I've been trying to get my head around the specifications so I buy the right one.
Take the one I linked above as an example, it's listed as 6.18N (63kg) at the top of...
I was thinking about making a kind of counterbalance weight. So I was looking this spring to make a constant torque motor.
https://www.ondrives.com/sr119
They come in many sizes but to take this one as an example it's listed as 6.18N (63kg) at the top of the page. At a glance considering the...
I am struggling through a problem in one of my designs and would appreciate some help.
Please refer to the image attached.
Problem Description:
S = Torsion spring
F = fixed point
T = tire
A tire is attached to a torsion spring through an arm as shown in the image. The torsion spring has one...
Tried to find the resultant force, but I can't see how the magnetic field affects. I used Faraday's law to find the the diferece of potentials in the plate Wich should be B.d.v, where v is the vertical velocity of plate, but there were not given the resistance or resistivity to relate with the...
So we know that all the energy originates from the spring:
E(spring) = (1/2)kd^2
As the block moves up the ramp, friction does work on the block over a distance of 2d:
W = μmgcos(θ)* 2d
So subtracting the work done by friction from the spring energy, gives us the energy left, so we'll set it...
"It should be able to accelerate from rest to 20 m/s at least 50 times before the spring needs winding"
-So F = -kd = -k(2.1) - d is 2.1 because it is the compression length
Now, since we know the d, divide it by 50, 2.1/50 = 0.042m
Basically, the spring unwinds 0.042 m 50 times for a total...
Let's say you have a box and there is a spring attached to it and the other end of the spring is attached to the wall. If you press the box towards the wall the spring presses back against the box with an equal force. F(push) = 20N, F(spring) = -kd. F(push) - F(spring) = F(net). Which is zero...
Problem Statement: A 2.0 kg cart and an 8 kg cart are connected by a relaxed, horizontal spring of spring constant 300 N/m. You pull the 8 kg cart with some constant horizontal force. The separation between the carts increases for a short time interval, then remains constant as you continue to...
I was wondering, I have an engine that should keep a spring compressed. How can I calculate the power necessary for this?
The work is Force x Distance, as there is no distance, there is no work, so no power... But obviously to keep the spring compressed the engine will have to produce a...
The question asks for a bunch of stuff, but I have everything except part d down.
a) Setting the mass of lemons as m1, I used m1*gh = 1/2mv^2, solving for v of the lemons as v = √2gh, where h is the height at which it is dropped. Then, I used COM and had this equation (not 100% sure if right)...
I am new to Simulink and I wanted to start practicing using a spring mass damper system. My first tutorial was this:
Later, I wanted to model a spring system where a mass moving at a known velocity hits the spring. The governing equation and a similar modeling method given in the previous...
Hello, do someone have time to help me out with an assignment?
My question
In the answer sheet they say:
What I do not understand is why m is withdrawn from both sides, since I don't see that those represent the same mass. When I did the assignment I thought m at the left side would be the...
I thought work is 0 because force is applying perpendicular to the spring's moving direction. these pulses are transverse pulse since those have amplitude, and pulse is moving horizontal, which means applying force horizontally, but spring is moving vertical. So my conclusion is "because pulse...
I want to know if my solution is correct:
The velocity of the center of mass immidiately after m1 has moved is just
vcm=m1v1 /(m1+m2)
I thing that i have to consider the spring and the m2
Hi all, I have a problem that I've been grappling with for the past 2 hours.
I was confident at first that I found the correct solution, but when I tried to verify I didn't have a constant in my v(x) function.
Here is my attempt:
I appreciate your help kind internet strangers!
Problem Statement: A known mass at a know velocity collides on a spring of known stiffness. What is the equation that governs the deceleration of the mass, so that the force on the spring could be found?
Relevant Equations: 1/2 m*V^2 = 1/2*k*x^2 + 1/2*m*(Vo)^2
Kinetic energy of mass before...
Hi. I have a question regarding the above image and want to know whether I am right or not. In the image there is a body with mass m and in the middle of the body there is a spring. The body is pulled upwards and then it hits two fixed rods such that the body cannot move upwards any more. Now...
I have the equation $$\frac{d^2y}{dt^2} + 5y = 0$$
where I've worked out $$y = Acos(\sqrt5t) + Bsin(\sqrt 5 t)$$
$$y'' = -5Bsin(\sqrt 5 t)
$$
using $$y = e^{\lambda x}$$ and using y(0) = 0 (the spring is released from equilibrium)
so an external force $$Acos(\omega(t - \phi))$$ is applied so...
Hello, I have a mass of 110 kg and I want to move it with a speed of 14 m/s by using springs. how can I determine the constant of the spring and design it? thank you!
First I worked out the dispersion relations, which is pretty easy:
##M \ddot x_j = K x_{j-1} + K x_{j+1} - 2K x_j -mg \frac {x_j} {l} ## (All t-derivatives)
We know ##x_j## will be in the form ##Ae^{ijka}e^{-i\omega t}##
so the above becomes:
## -\omega^2M = K (e^{-ika}+e^{ika}-2)-\frac {g}...
Hi,
Most of the spring vibration lectures assume spring to be fixed on one end and mass on the other end [Example]. In my case, spring has a sinusoidal excitation on one end and mass on other end. Pl. refer the image below.
How to get the governing equation? With that I also want to find the...
The spring constant of a helical spring is 28 N mñ1. A 0.40 kg mass is suspended from the
spring and set into simple harmonic motion of amplitude 60 mm.
i use the equation 1/2 change in extension times by force where the force i assume is mass times by 9.8
but the mark scheme uses 1/2 kx ^2 and...
Hi, Working on my vehicle and have a theoretical question I'd like a 2nd opinion on. The physics question is how much influence the force of a bump has in conjunction with a perfectly tuned spring rate can have on ride quality (as crudely defined in vertical acceleration z force m/s squared)...
On object 2: There are only 2 horizontal forces - Friction and Tension (of the spring).
T = km2g
On Object 1: There are 3 horizontal forces and the minimum value for F is when:
F - km1g - km2g = 0
F = kg(m1 + m2)
However, Solution is:
F = kg(m1 + 0.5 m2)
Any opinion?
W_net = Integral from 0 to 0.70 meters [ - F_spring - F_friction ]
= 1/2 * (-k) * x^2 - mu * mg * normal force * x
= 1/2 * (-325N/m) * (.70)^2 - 0.250 * 6kg * 9.81m/s^2 * 0.70 - 0
= - 89.93 Joules
Is this correct and am I setting this whole thing up correctly? The negative signs have me...