- #1
LGS1970
- 2
- 0
Homework Statement
You have 1.0kg of ice at 0.0 deg C in a pot on a stove that produces 900 W of power. Assuming that the pot and the stove are 'perfect' (i.e., no heat lost) and ignoring the heat capacity of the pot, compute the time it will take for this ice to boil away completely.
Homework Equations
Power * time = Mass * Specific Heat * Temperature (or maybe change in temp?!)
The Attempt at a Solution
I used the equation above ^ and used the specific heat for ice of 2106 J/(kg/K) and 4218 j/(kg/K) for liquid. but I don't think this is right because what would the change in temp be for the ice to liquid phase and vapor to completely gone phase? Really confused