- #1
Puchinita5
- 183
- 0
I don't know why, but I just can't figure this out.
"Calculate the electrode potential for a silver filled electrode in a solution of 0.00550 M AgNO3 solution."
I got that
Ag+ + e- --> Ag(s) had an E* = .80V
I got that the answer is E=.80 - .0592 log (1/.00550M)= .6655 V
But why do you put 1/.00550M in the parenthesis?
My first thought was that AgNO3 + e- --> Ag(s) + NO3-
and that the concentreation of AgNO3 is the same as NO3.
so that it would be log(1) , which is wrong.
I just don't get the concept I guess.
"Calculate the electrode potential for a silver filled electrode in a solution of 0.00550 M AgNO3 solution."
I got that
Ag+ + e- --> Ag(s) had an E* = .80V
I got that the answer is E=.80 - .0592 log (1/.00550M)= .6655 V
But why do you put 1/.00550M in the parenthesis?
My first thought was that AgNO3 + e- --> Ag(s) + NO3-
and that the concentreation of AgNO3 is the same as NO3.
so that it would be log(1) , which is wrong.
I just don't get the concept I guess.