- #1
Buri
- 273
- 0
The question says:
Show that if Q = [a1,b1]x...x[an,bn] is a rectangle, the Q equals the closure of Int Q.
The definition of closure that I have is Cl(A) = int(A) U bd(A). So I'd like to show that Cl(int(Q)) = int(int(Q)) U bd(int(Q)).
But this just seems to be obvious to me which just makes it hard to prove - I just don't know what to write. Any hints/ideas on how to prove this rigorously?
EDIT!
I guess I'd have to show something like:
Int(AxB) = Int(A)xInt(B)
And then I guess, I'd make a claim that bd(int(Q)) = {a1,b1,...,an,bn} and prove this by showing that no other boundary points exist?
Questions like this I always find hard.
Show that if Q = [a1,b1]x...x[an,bn] is a rectangle, the Q equals the closure of Int Q.
The definition of closure that I have is Cl(A) = int(A) U bd(A). So I'd like to show that Cl(int(Q)) = int(int(Q)) U bd(int(Q)).
But this just seems to be obvious to me which just makes it hard to prove - I just don't know what to write. Any hints/ideas on how to prove this rigorously?
EDIT!
I guess I'd have to show something like:
Int(AxB) = Int(A)xInt(B)
And then I guess, I'd make a claim that bd(int(Q)) = {a1,b1,...,an,bn} and prove this by showing that no other boundary points exist?
Questions like this I always find hard.
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