Oscillator Differentials: What's a physical meaning of complex part of the solution for coordinate change of the anharmonic oscillator?

  • #1
DifferentialGalois
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Homework Statement
What's a physical meaning of, for example, complex part of the solution for coordinate change of the anharmonic oscillator?
Why after substitute (for diff. equation solve) for real x we can earn ##x = Re(z) + iIm(z)##? Is it because of substitutio?
Relevant Equations
##x = Re(z) + iIm(z)##
##x(t)=e^{i\alpha t}##
##x(t) = A e^{i \alpha_1 t} + B e^{i \alpha_2 t}##
I don't understand what the question means, and the answer is provided here: https://physics.stackexchange.com/a/35821/222321
Could someone provide a comprehensive one-by-one explanation.
 
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  • #2
The discussion at that link does not, as far as I can see, provide a physical meaning to the complex solution. Neither does it address anharmonicity, so I assume you mean just a standard damped (maybe forced) oscillator.
If we map the state onto the complex plane, the graph as a function of time (an axis normal to that plane) becomes a helix, tapering exponentially in the case of unforced. I would think this could be realised in a physical system.
 
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  • #3
bump
 
  • #4
DifferentialGalois said:
bump
Why are you bumping your thread and not replying to @haruspex ?
 
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  • #5
berkeman said:
Why are you bumping your thread and not replying to @haruspex ?
i need an explanation to the mathematical equations.
 
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  • #6
DifferentialGalois said:
i need an explanation to the mathematical equations.
I thought I saw a pretty good explanation in the post by @haruspex -- Which part of what he wrote did you not understand?
 

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