Exploring Orbital Velocity: Significance and Applications

In summary, the speaker has just finished a course in astronomy and is curious about the significance of the boundary where the orbital velocity is equal to the speed of light. They have discovered that this boundary is inside the event horizon and is known as the photon sphere. It is a coincidence that the Newtonian calculation gives the correct result for the Schwarzschild radius, as it breaks down under extreme conditions and must be replaced with General Relativity. This can be done through corrections or using the full theory of GR.
  • #1
travwg33
21
0
I am fairly new to astronomy, having just finished a course this past semester in high school, and I have a question about orbital velocity.

Now, I know that the event horizon is the boundary at which the escape velocity is equal to the speed of light, but is there any significance to the boundary at which the orbital velocity is equal to the speed of light?

I quickly messed around with the math to see where such a boundary would lie and determined this:
Vorb = √((Gm)/r)

substitute Vorb for C

C = √((Gm)/r)
r = (Gm)/(C2)

This is obviously very similar to determining the Schwarzschild radius and this boudary would actually be inside the event horizon, light orbiting the singularity, but never moving out past the radius once in orbit.

I looked online to see if such a boundary was important or existed and I think I found something similar the photon sphere, but the equation is different and this sphere is outside the event horizon.

Does the boundary where r = (Gm)/(C2) mean anything?
 
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  • #2
Does the boundary where r = (Gm)/(C2) mean anything?
No. It's a coincidence that a Newtonian calculation gives the correct result for the Schwarzschild radius (he's not a child, btw). You can't expect that it works for other qunatities.
If you do the calculations in GR, you get the photon sphere result. For illustration, think that the centrifugal force reverses direction near the horizon, where relativity becomes important. Thus, it's even harder to orbit than to escape.
 
  • #3
Ah ok that makes sense. Thanks for clarifying that up :)
 
  • #4
Just thinking, I do not know too much about Newtonian mechanics or GR, but does this mean that NM breaks down under extreme conditions?
 
  • #5
Exactly. It works if you have small velocities and weak gravity. It's like a first order approximation to the exact GR laws.
You can make it work more exactly or for more extreme circumstances if you include some corrections, like a second order approximation to GR. That's called the Post-Newtonian formalism.
Under the most extreme conditions, you use full GR.
 

Related to Exploring Orbital Velocity: Significance and Applications

1. What is orbital velocity?

Orbital velocity is the speed at which an object must travel in order to maintain a stable orbit around another object, such as a planet or a star.

2. How is orbital velocity calculated?

Orbital velocity is calculated using the formula v = √(Gm/r), where v is the orbital velocity, G is the gravitational constant, m is the mass of the central object, and r is the distance between the two objects.

3. What factors affect orbital velocity?

The factors that affect orbital velocity include the mass of the central object, the distance between the two objects, and the gravitational constant.

4. Can orbital velocity change?

Yes, orbital velocity can change depending on the factors mentioned above. For example, if the distance between two objects changes, the orbital velocity will also change.

5. How is orbital velocity related to escape velocity?

Escape velocity is the minimum speed an object needs to have in order to escape the gravitational pull of a celestial body. Orbital velocity is related to escape velocity in that if an object's orbital velocity is greater than the escape velocity, it will leave the orbit and enter a new trajectory.

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