Calculating load for tidal movement

[jamesd442001]

Calculating wind load is wind speed squared x .00431 x area in sq. ft. A 5 mph wind with a vertical 100 sq. ft. wing is 10.77 lbs. The mass of salt water is around 854 times greater than the mass of air. Can you use the wind formula and multiply by 854? Does the weight of water at different atmospheres change this?

 

[stewartcs]

Calculating wind load is wind speed squared x .00431 x area in sq. ft. A 5 mph wind with a vertical 100 sq. ft. wing is 10.77 lbs. The mass of salt water is around 854 times greater than the mass of air. Can you use the wind formula and multiply by 854? Does the weight of water at different atmospheres change this?

What is the context of this question? Various standards would apply and have things such as shape coefficients that will change the resultant force from environmental loadings.

The type of hull (presumably this is for an ocean vessel) may also introduce other factors to consider.

That being said, the final calculation will be some derivative of the basic equation:

F = PA

API 2SK is a good reference for this. For a ship hull the current force on the bow or stern (in lbf) is:

[tex]F_{cy} = C_{cy}SV_c^2[/tex]

where,

S = wetted surface area of hull including appendages (ft^2)
V_c = current speed (knots)
C_cy = current force coefficient = 0.40 lbf/(ft^2 - knots)

Hope this helps.

CS

 

[oswaler]

Thank you for sharing this information about calculating load for tidal movement. I would like to provide some additional insight into this topic.

Firstly, it is important to note that the formula for calculating wind load is typically used for structures or objects that are exposed to wind, such as buildings, bridges, or towers. It may not be applicable to calculating load for tidal movement, as the forces and dynamics involved in tidal movement are different from those caused by wind. Therefore, it may not be accurate to use this formula for tidal movement.

Secondly, even if we were to apply the wind load formula to tidal movement, it is not appropriate to simply multiply it by 854 to account for the mass of salt water being 854 times greater than air. This is because the formula is based on the density of air, not water. The density of air is approximately 1.2 kg/m^3, while the density of salt water can vary depending on salinity, temperature, and depth. Therefore, simply multiplying the wind load formula by 854 would not accurately account for the differences in density between air and water.

Lastly, the weight of water at different atmospheres may have some impact on tidal movement, but it is not the only factor to consider. Other factors such as water depth, tides, and currents also play a significant role in determining the load and forces involved in tidal movement. Therefore, it is important to consider all of these factors when calculating load for tidal movement, rather than relying solely on a wind load formula.

In conclusion, while the wind load formula may provide some insights into the forces involved in tidal movement, it may not be the most accurate or appropriate method for calculating load in this scenario. As scientists, it is important to consider all relevant factors and use appropriate methods and formulas for accurate and reliable calculations.