Recent content by scottdave

I am trying to think of the usefulness of the information in the gray graph - average speed of remaining trip. This is not like predicting how much time is remaining. You calculate only after you know the total time, if I understand you correctly.

What data are you measuring to get the grey graph?

What does ms stand for?

Showing the intermediate step where you group the radicals and simplify the denominator may help reveal the mistake.

See this video for an interesting demonstration and working out for the acceleration in a circular path. Note, for a circular path, the acceleration direction is changing - it points toward the center of the circle as the object moves. Friction actz on the skate blade. So the boy can change...

Acceleration and Force are vectors with both magnitude and direction. In a circular path, the magnitude of the acceleration is constant, but the direction is always toward the center of the circle. So this is not constant acceleration.

I think use in the switching yard makes sense if it is also using regenerative braking. There is a lot of starting and stopping in the switch yard.

This is interesting. The first thing that came to mind were diesel-electric submarines.

This is from 2007. I'm not sure why it is popping up now... The OP has answered its own questions. It looks correct except for a misplaced parenthesis in part c: at^(2/2) should be a(t^2)/2 and correct units would be helpful.

I saw a similar map gor AirBnB bookings on the news Friday

I wonder what is going on at those 2 spots in North Carolina?

Ha! :woot: These Unanswered Questions just show up... and I'm so into trying to help - I forget to look at the date.

What value frequency did you calculate? What did they provide as the correct answer? Why do you divide by Xc to get the current?

Rather than saying T - mg, I would consider them as vectors, since g is down it is negative. Then you have: ma = T+ mg

With a reference direction of up is positive, then if it is moving down (negative) a positive acceleration will result in it slowing down (decelerate).