Thank you very much, I was able to get the correct answer!
I finally realised that the maximum shear stress applies at y=0, but the shear stress provided is for the glued joints at y = 1cm, therefore I can't just use the equation for maximum shear stress.
Thank you for your reply!
I think it is at x=0 and x=l, therefore the value F I obtain from the equation is P_max/2?
In that case I'm getting 5*10^6*(4*6*10^-4)*(2/3) = 8000, which is not 9000 as the given answer suggests and I don't know why.
I have tried to calculate the safe load with the equation of maximum shear stress, A = 4*6*10^-4, and the given shear stress 5MPa, but I couldn't seem to get the right answer which is 18kN.
After crossing out all the variables which I think equals 0 in the equation, I was left with:
∆PE + ∆U = Qin
mg (0.2) + ∆U = 300
10*9.81*0.2 - 300 = - ∆U
= -280J
This was the answer I derived. However, the correct answer was supposed to be 123.3J. Please can someone explain to me how to get...
I'm sorry, this is my first time using Physics Forum and I wasn't sure about the rules. Thank you for the reminder! I tried to add the question, is it better now?
Summary:: I need some help with moment when using equations of equilibrium
Edit: Sorry I forgot to say what the question was! The question was to solve the value of R based on the diagram below alone.
I was solving the question below and I tried to resolve R into a force that is perpendicular...