Recent content by josevie

@haruspex has completely annihilated any doubts I had. Thanks for taking your time to help me!

That is one of the most enlightening answers I have ever read, thanks so much!!!

Indeed, I was trying to solve using work and energy. The stone is at rest, however, so it has no Kinect energy. Is right of me to say that the system has no potential energy too? And that the only way for it to have any potential energy would be for a external force do work on the system to...

I see now my mistake of trying to use work for a system that is on rest, thanks. That, however makes me question other things: So, if is at rest it means that -k.x = m.g, right? Does normal force has no part in it? It just came to me that I don't understand why normal force is not considered...

It is to my understanding that if the spring was compressed 10cm, it is due to the Work of the Weight Force of the stone. So: Work done on the spring by the stone = m.g.x = 7.84 J The work done on the spring will be stored as potential energy of the spring, so: Us = W Us = (1/2).k.x² k =...